(x^2+5)-(2x-8)=0

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Solution for (x^2+5)-(2x-8)=0 equation:


Simplifying
(x2 + 5) + -1(2x + -8) = 0

Reorder the terms:
(5 + x2) + -1(2x + -8) = 0

Remove parenthesis around (5 + x2)
5 + x2 + -1(2x + -8) = 0

Reorder the terms:
5 + x2 + -1(-8 + 2x) = 0
5 + x2 + (-8 * -1 + 2x * -1) = 0
5 + x2 + (8 + -2x) = 0

Reorder the terms:
5 + 8 + -2x + x2 = 0

Combine like terms: 5 + 8 = 13
13 + -2x + x2 = 0

Solving
13 + -2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + -2x + -13 + x2 = 0 + -13

Reorder the terms:
13 + -13 + -2x + x2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -2x + x2 = 0 + -13
-2x + x2 = 0 + -13

Combine like terms: 0 + -13 = -13
-2x + x2 = -13

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -13 + 1

Reorder the terms:
1 + -2x + x2 = -13 + 1

Combine like terms: -13 + 1 = -12
1 + -2x + x2 = -12

Factor a perfect square on the left side:
(x + -1)(x + -1) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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